PHP Parse error

<?php
$this_is_my_array = array("John","Johan");
for(int i = 5; i < 5; i++){
echo "$this_is_my_array[i] ";
}
//Adding name Markus
array_push($this_is_my_array,"Markus");
for(int i = 5; i < 5; i++){
echo "$this_is_my_array[i] ";
}
//Removing name from array
$this_is_my_array2= array_pop($this_is_my_array);
for(int i = 5; i < 5; i++) {
echo "$this_is_my_array2[i] ";
}

I just playing/learning php but this code gives me error.

PHP Parse error: parse error, expecting ';' in C:\main.php php on line 3

What im going wrong?

From stackoverflow

• For starters, your variable i should be $i, with a dollar sign. That's the bulk of your error. But there's a few other problems. Try this.

  echo("start");
  
  $this_is_my_array = array("John","Johan");
  for($i = 5; $i < 5; $i++){
      echo $this_is_my_array[$i];
  }
  
  //Adding name Markus
  array_push($this_is_my_array,"Markus");
  for($i = 5; $i < 5; $i++){
  echo "$this_is_my_array[$i] ";
  }
  //Removing name from array
  $this_is_my_array2= array_pop($this_is_my_array);
  for($i = 5; $i < 5; $i++) {
  echo "$this_is_my_array2[$i] ";
  }
  
  
  echo "end";
  

  But look at your for loop, it says

  $i = 5

  while $i is less than 5, do something

  But $i is already 5.

• Variable i should be $i. Lose the quotes when outputing the array, not needed.

  Do this:

  for($i = 5; $i < 5; $i++)
  

• for(int i = 5; i < 5; i++){
  

  should be

  for($i = 5; $i < 5; $i++){
  

  You're mixing in C-style syntax. Variables should always begin with $

  Daan : Did you also remove the 'int' declaration, or only added the $?

  Gumbo : Variables *must* always begin with a $.

  Mark : you know...aside from the parse error there's also a logic error we all missed. $i = 5; $i < 5? that loop will never run. it should start from 0. you also have an error on line 4, should be echo $this_is_my_array[$i].' '; but, indices 2,3,4 will be empty anyway...technically undefined

  Mark : also... $this_is_my_array2 will only contain the last element in $this_is_my_array, not a copy of the array minus the last element. read the documentation http://ca3.php.net/manual/en/function.array-pop.php perhaps you should start learning variables and echos before you jump into arrays

• There is no need to specify i as an integer – if you need to explicitly typecast i as an integer, you can do it like this:

  $i = (int)$i;
  

  Also, all variables must be preceded by a dollar sign $.

• Your loop will never loop because $i is always 5.

  Try this to get some results:

  <?php
  $this_is_my_array = array("John","Johan");
  for($i = 1; $i < 5; $i++){
  echo $this_is_my_array[$i] ;
  }
  //Adding name Markus
  array_push($this_is_my_array,"Markus");
  for($i = 1; $i < 5; $i++){
  echo $this_is_my_array[i];
  }
  //Removing name from array
  $this_is_my_array2= array_pop($this_is_my_array);
  for($i = 1; $i < 5; $i++) {
  echo $this_is_my_array2[i] ;
  }
  ?>